Problem: Quadratic functions and vertex

Problem

For an arbitrary quadratic function \(y=ax^2+bx+c\) you can show that the \(x\) -coordinate of the vertex is given by \(x=-b/2a\) . You get the \(y\) -coordinate simply by plugging in the \(x\) -value in the function or, alternatively, by evaluating \(y=c-b^2/4a\) .

Find the vertex of the function \(y=x^2-2x+1\) .